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User forums => Help => Topic started by: 1439808922 on May 05, 2016, 10:30:09 am

Title: No console output when debug with arguments
Post by: 1439808922 on May 05, 2016, 10:30:09 am

int main(int argc,char *argv[])
{
for(int i=0;i<argc;i++)
    printf("%s ",argv);

return 0;                                     -----breakponit

}

the above code has  no console output  .

But

int main(int argc,char *argv[])
{
int a;
for(int i=0;i<argc;i++)
    printf("%s ",argv);
scanf("%d",&a);

return 0;                       
}

does have output.


what should i do???

Title: Re: No console output when debug with arguments
Post by: 1439808922 on May 05, 2016, 10:38:07 am

it seems that i should fflush(stdout)  manually  when debugging with arguments????

Title: Re: No console output when debug with arguments
Post by: raynebc on May 05, 2016, 09:28:46 pm

In your loop, did you mean to do this instead (print each command line argument to console)?

Code

for(int i=0;i<argc;i++)
    printf("%s ",argv[i]);

Title: Re: No console output when debug with arguments
Post by: 1439808922 on May 06, 2016, 06:02:19 am

yes