User forums > General (but related to Code::Blocks)

do I understand C++ wrong?

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sethjackson:
The ClassB::Function(const char* str) is different than the ClassA::Function(). You declare ClassB, and then try not passing a param to Fuction(const char* str). You cannot do this since Fuction(const char* str) requires a param. Some C++ guru could answer this better I'm sure, but that is the way the compiler works AFAIK. So why don't you declare ClassA, and call that Function()?

MoonKid:

--- Quote from: sethjackson on April 22, 2006, 03:16:45 pm ---So why don't you declare ClassA, and call that Function()?

--- End quote ---

I want to have an object with a to Function() methodes, one with and one without a parameter.
Logicly (in my framework) they should be in different classes.

I will think about how to design it compilable

thomas:

--- Code: ---class ClassB : public ClassA
{
    public:
        using ClassA::Function;
        bool Function (const char* str)
        {
            return true;
        }
};
--- End code ---

Ceniza:
Your problem is the compiler hides A::Function and it's natural C++ behavior.

You could have lots of different signatures of Function in ClassA. If you make ClassB inherit from ClassA, ClassB will have all those Function too, but if you add a method in ClassB with the name Function (just what you're doing), every inherited signature of Function will be hidden.

To make ClassA::Function visible in ClassB do this (Thomas was faster):


--- Code: (cpp) ---class ClassB : public ClassA
{
    public:
        using ClassA::Function;

        bool Function (const char* str)
        {
            return true;
        }
};
--- End code ---

Another way is to change your main to this:


--- Code: (cpp) ---int main()
{
ClassB b;

b.ClassA::Function();

return 0;
}
--- End code ---

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