Author Topic: Are Scripted Wizards without license?  (Read 753 times)

Offline stahta01

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Are Scripted Wizards without license?
« on: October 03, 2022, 01:22:17 am »
I am using the CB Scripted wizard to create some simple projects? Do any of them have a license that is not mentioned in a source file?

Link to my git repo https://github.com/stahta01/mingw64_gcc_toolchain_test_cbprojects

I am having weird issues building MinGW64 GCC 4.8.x that are likely CRT/GCC/Binutils caused problems.
I am hoping these test project will help determine which part has the problem.

Tim S.
C Programmer working to learn more about C++ and Git.
On Windows 7 64 bit and Windows 10 32 bit.
On Debian Stretch, compiling CB Trunk against wxWidgets 3.0.
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When in doubt, read the CB WiKi FAQ. http://wiki.codeblocks.org

Offline stahta01

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Re: Are Scripted Wizards without license?
« Reply #1 on: October 03, 2022, 01:58:49 am »
The ones a simple search on copyright found
Code
Copyrighted by:
  HighTec EDV-Systeme GmbH
    multiple .h, .c, .S, and .x files
  http://www.resedit.net
    resource.rc
  Free Software Foundation
    multiple Makefile.in and Makefile
C Programmer working to learn more about C++ and Git.
On Windows 7 64 bit and Windows 10 32 bit.
On Debian Stretch, compiling CB Trunk against wxWidgets 3.0.
--
When in doubt, read the CB WiKi FAQ. http://wiki.codeblocks.org

Offline ollydbg

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Re: Are Scripted Wizards without license?
« Reply #2 on: October 04, 2022, 08:03:24 am »
My guess is that the Scripted file should be in GPL, and the template source code(sample.cpp files) should be public domain.
« Last Edit: October 04, 2022, 08:20:12 am by ollydbg »
If some piece of memory should be reused, turn them to variables (or const variables).
If some piece of operations should be reused, turn them to functions.
If they happened together, then turn them to classes.