On a Win10 box I currently use C::B 11530 with MSVC2013 compiler.
For debugging under Windows, I prefer to use the debugger in Visual Studio. To do this, I create an entry in the C::B Tools menu to start the Visual Studio IDE/Debugger with the current source file and at the current editor line:
/edit $(ACTIVE_EDITOR_FILENAME) /command "edit.goto $(ACTIVE_EDITOR_LINE)" /debugexe $(TARGET_OUTPUT_FILE)
See attached image for full details, this works fine with Visual Studio 2013 Professional and with slightly different syntax you can do the same with the free Visual Studio 2013 Express. It opens the currently active source file correctly, but no other source files.
I usually work with several projects at once (in a Workspace) and typically have several editor windows open. What I am missing is a way to automatically open all the same source files that are currently open in C::B also in Visual Studio debugger. To experiment, I found that $(ALL_PROJECT_FILES) will work as advertised, it opens all the current project files, but that is not what I want. Instead I think something like the imaginary $(ALL_OPEN_FILES) would do the trick, i.e. $(ALL_OPEN_FILES) would evaluate to full paths to all currently open source files in the C::B IDE, including files from different C::B projects.
Then I would specify:
/edit $(ACTIVE_EDITOR_FILENAME) /command "edit.goto $(ACTIVE_EDITOR_LINE)" $(ALL_OPEN_FILES) /debugexe $(TARGET_OUTPUT_FILE)
Is there perhaps a C::B variable somewhere to do this already?